davrot/pytutorial
1
0
Fork 0
Code Issues Pull requests Projects Releases Packages Wiki Activity Actions

Update README.md

Browse source 
Signed-off-by: David Rotermund <54365609+davrot@users.noreply.github.com>
This commit is contained in:
David Rotermund 2023-12-02 20:50:16 +01:00 committed by GitHub
parent 74374e5f74
commit 7dd52e7e59
No known key found for this signature in database
GPG key ID: 4AEE18F83AFDEB23
1 changed files with 7 additions and 7 deletions
Show stats Download patch file Download diff file Expand all files Collapse all files

14
matlab/3/README.md
View file

@ -29,7 +29,7 @@ A major advantage of Matlab in comparison to a conventional programming language
| | | |
| ------------- |:-------------:|:-------------:|
| `a = [3;1];` | defines a column vector | $\vec{a} = \left(\begin{array}{c}3\\1\\\end{array}\right)$ |
| `a = [3;1];` | defines a column vector | $\vec{a} = \left(\begin{array}{c}3 & 1 \end{array}\right)$ |
| `a(k)` | means the vector component | $a_k$ |
| `b = [0,3,-4];` | defines a row vector | $\vec{b} = (0,3,-4)$ |
@ -43,29 +43,29 @@ $3x+y = 1 $
can be formulated elegantly:
$$ \left(\begin{array}{cc} 1 & 2 \\\\ 3 & 1 \\ \end{array}\right) \left(\begin{array}{c} x & y \\\\ \end{array}\right) = \left(\begin{array}{c} 3 & 1 \\\\ \end{array}\right) $$
$$ \left(\begin{array}{cc} 1 & 2 \\ 3 & 1 \end{array}\right) \left(\begin{array}{c} x & y \end{array}\right) = \left(\begin{array}{c} 3 & 1 \end{array}\right) $$
respectively
$D\,\vec{x} = \vec{b} $
$$D\,\vec{x} = \vec{b} $$
with the $2\times 2$ matrix
$ D = \left(\begin{array}{cc}1 & 2\\3 & 1\\\end{array}\right) \begin{array}{c}\leftarrow\;\;\mbox{1. line}\\\leftarrow\;\;\mbox{2. line}\\\end{array}$
$$ D = \left(\begin{array}{cc}1 & 2 \\ 3 & 1 \end{array}\right) \begin{array}{c}\leftarrow\;\;\mbox{1. line} \\ \leftarrow\;\;\mbox{2. line} \\ \end{array}$$
$\nearrow$ $\nwarrow$
$$\nearrow \nwarrow$$
1. line 2. line
and the column vectors
$ \vec{x} = \left(\begin{array}{c}x\\y\\\end{array}\right) \quad\mbox{and}\quad \vec{b} = \left(\begin{array}{c}3\\ 1\\\end{array}\right) $.
$$ \vec{x} = \left(\begin{array}{c}x & y \end{array}\right) \quad\mbox{and}\quad \vec{b} = \left(\begin{array}{c}3 & 1 \end{array}\right) $$
Here, $\vec{x}$ is the solution vector being sought.
The formal solution of the equation $D\,\vec{x} = \vec{b}$ is given by
$\vec{x} = D^{-1}\, \vec{b} \, ,$
&$\vec{x} = D^{-1}\, \vec{b} \, ,$&
where $D^{-1}$ denotes the inverse of the matrix $D$.